2x-(16/r^2)=0 - solution

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Solution for 2x-(16/r^2)=0 equation:

D( x )

r^2 = 0

r^2 = 0

r^2 = 0

r^2 = 0

x należy do R

x belongs to the empty set

2*x-(16/(r^2)) = 0

x belongs to the empty set

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